Question

a train starting from rest moves with a uniform acceleration of 0.2 metre per second for 5 minutes calculate the speed acquired and the distance travelled in this time

Answer 1

u=0
a= 0.2m/s
t=5m= 5×60=300s
the speed is
v=u+at
v=o+0.2×300
v=60m/s
the distance is
s=ut + 1/2at^2
s=0×300+1/2×0.2×(300)^2
s=0+1/2×0.2×90000
s= 9000m