Question

A train starting from rest moves with a uniform acceleration of 0.2 m/s²  for 3 minutes. What is the distance travelled in this time?​

Answer 1

Answer:

Distance is 3.24 km

Step-by-step explanation:

Initial velocity, u=0m/s

Acceleration, a = 0.2 m/s2

distance , s = ?

Time, t= 3min =5 × 60 = 180sec

the distance travelled is

s=ut+ 1/2 αt2

s= 0× 180 + 1/2 × 0.2 × 180 × 180

s= 0+3240 = 3240 m = 3.24 km