Question

a train starting from rest moves with a uniform acceleration of 0.2 m per second square for 5 minutes calculate the speed acquired and the distance travelled in this time

Answer 1

u=0m/s

v= to be found

a=0.2m/a²

t=5 min = 300 sec

using first equation of motion

v=u+at

v=0+0.2×300= 0+ 60 = 60 m/s

now v = 60m/s

using second equation of motion

s = ut+1/2at²

s=0×0.2 + 1/2 × 0.2 × 300 × 300

s= 0+1/2 × 150 × 0.2 × 300

s= 9000m = 9km

Hope this helps

thanx and be brainly.........................................................................