A train starting from rest moves with a uniform acceleration of 0.2m/s² along a straight track. The time required to attain a velocity of 50 km/h
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Using Newton's third equation of motion i.e.
v² - u² = 2as
Here : v = 0 m/s
u = 72km/h = 72*(5/18) = 20m/s
a = -0.2 m/s²
0 - 20²= 2*(-0.2)*s
s= 1000 m i.e. 1 km
P.s. Units of acceleration you have given in the question is incorrect. Its m/s² not m/s.
Hope it was helpful :)
v² - u² = 2as
Here : v = 0 m/s
u = 72km/h = 72*(5/18) = 20m/s
a = -0.2 m/s²
0 - 20²= 2*(-0.2)*s
s= 1000 m i.e. 1 km
P.s. Units of acceleration you have given in the question is incorrect. Its m/s² not m/s.
Hope it was helpful :)
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