Question

a train starting from rest moves with a uniform acceleration of 0.2 metre per second square for 5 minutes calculate speed acquired and the distance travelled​

Answer 1

u = 0

a = 0.2 ms^-2

t = 5 min = 300s

v = ?

s = ?

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v = u + at

v = 0 + 0.2×300

v = 60 m/s

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v² - u² = 2as

60² - 0² = 2×0.2×s

3600 = 0.4×s

$\frac{3600}{0.4}$ = s

s = 9000m

= 9km

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