Question

a train starting from rest moves with a uniform acceleration of 0.2 metre per second square for 5 minutes calculate the speed acquired and the distance travelled in this time​

Answer 1

here,

The initial speed is u =0

The Final speed is v

Acceleration=a=0.2 m/sec²

time = 5 minutes= 300 seconds

By formula,

a = v-u /t

0.2 × 300 =v

v = 60 m/sec

Now , the distance travelled

= >> speed ×time

>> 60× 300

>>18000 meters

>>18 Km