Question

a train starting from rest moves with uniform acceleration 0.05m/s. calculate speed acquired and distance travelled by the train. ​

Answer 1

Initial velocity, u=0m/s

Final velocity, yv=?

Acceleration, a=0.2m/s

2

Time, t=5min=5×60=300sec

Using first equation of motion to obtain the final speed:

v=u+at

v=0+0.2×300=60m/s

And the distance travelled is

s=ut+

2

1

αt

2

s=0×300+

2

1

×0.2×300×300

s=0+9000=9000m=9km