A train starting from rest moves with uniform acceleration of 5 M per second square. Find its velocity when it has travelled a distance of 1 kilometre.
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u=0m/s
a=5 m/s square
distance =1km
= 1000 m
From 3rd equation of motion
v square - u square = 2as
v square -0= 2×5×1000
v square =10000
v = 100 m/s
Mark this answer as branliest if it helped you...
⛥⛥⛥⛥⛥
u=0m/s
a=5 m/s square
distance =1km
= 1000 m
From 3rd equation of motion
v square - u square = 2as
v square -0= 2×5×1000
v square =10000
v = 100 m/s
chunmun30:
Mark this answer as branliest if it helped you
Answered by
30
Answer
given. the starts from rest so
initial velocity (u) = 0 m/s
acceleration (a) = 5 m/s^2
velocity when it has traveled distance of 1 kilometer
we know that 1 km = 1000 m......
from third equation of motion we know that
v^2 - u^2 = 2as
v^2 - 0^2 = 2 ( 5 ) ( 1000)
= v^2 = 10 * 1000 = 10000
v^2 = 10000
√v^2 = √10000
v = 100 m / s
given. the starts from rest so
initial velocity (u) = 0 m/s
acceleration (a) = 5 m/s^2
velocity when it has traveled distance of 1 kilometer
we know that 1 km = 1000 m......
from third equation of motion we know that
v^2 - u^2 = 2as
v^2 - 0^2 = 2 ( 5 ) ( 1000)
= v^2 = 10 * 1000 = 10000
v^2 = 10000
√v^2 = √10000
v = 100 m / s
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