Question

a train starting from rest moves with uniform acceleration of 0.2 metre per second square for 5 minutes calculate the speed acquired and the distance travelled in this time​

Answer 1

(i) To find the speed acquired

First equation of motion

v=at+u

v=0.2X5X60+0 (60 to change minutes into seconds)

v=0.2X300

v=60m s^1

(ii)To find distance traveled in this time

Second equation of motion

s=ut+1/2at^2

s=0X300+1/2X0.2X300X300

s=1/2X60X300

s=60X150

s=9000 meter

or

s= 9 kilometer

Answer 2

Please collect the answer