A train starting from rest moving with a uniform acceleration attains a speed of 36km/hr in 10 sec. Find its acceleration
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First convert km/hr into m/s,
36*5/18=10 m/s
u=0;v=10;t=10s
using the first equation v=u+at
10=0+10t
=> 10/10=t
=>1 =t
therefore 1 m/s is the acceleration
36*5/18=10 m/s
u=0;v=10;t=10s
using the first equation v=u+at
10=0+10t
=> 10/10=t
=>1 =t
therefore 1 m/s is the acceleration
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