a train starting from rest obtain a velocity 72 km per hour in a five minutes with a uniform acceleration find the acceleration
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velocity in m/s = 72×5/18= 20m/s
five min = 300 sec
v=u+at
20=0+a × 300
a=20/300
=0.06m/s^2
five min = 300 sec
v=u+at
20=0+a × 300
a=20/300
=0.06m/s^2
harshitraj53:
wrong
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i hope ye sahi higa.........
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