Question

A train starting from rest picks up a speed of 20 m/s in 20 s while travelling on a straight path. It continues to

move at the same speed for the next 50 s. It is then brought to rest in the next 10 s.

a. Plot the speed-time graph for the train.

b. Calculate its acceleration and retardation.

c. Calculate the distance covered by the train when it was i) travelling at the same speed, ii) retarding.

d. Calculate the average speed during retardation.

e. How much distance did the train cover during this entire journey?​

Answer 1

Answer:

Here is your answer

13 KM

Explanation:

S = S₁ + S₂ + S₃ = Total distance covered

      =  1/2 × 200 × 20 + 500 × 20 + 1/2 × 100 × 20

     =   2,000 + 10,000 + 1,000

     =   13,000 M

     =   13,000/100

     =   13 KM

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