Question

A train starting from rest travels with uniform acceleration and acquires a velocity of 60km/h in 2 mins. Find the acceleration and distance travelled in time

Answer 1

Explanation:

V=U+at

First we will convert everything into m/s

so

v=60*5/18

v=100/6 m/s

t=2 min

t=2*60

t=120 sec

u=0

so now by formula

100/6=0+a120

a=100/120*6

a=10/72 m/s² or (10/72)*(5/18)=8km/h

s=ut+1/2 at²

s=0*120+(1/2) (10/72)120²

s=(5/72)*14400

s=5*200

s=1000m or 1km

Thank you

Regards

Answer 2

Answer:-

a = 0.138m/s²

s = 1005.6m

Given:-

u = 0m/s

v = 60 km/hr

Change in to SI units ,

= 60 × 5/18

= 16.66 m/s

t = 2minutes or 120s

To find :-

The acceleration and distance travelled by car.

Solution,

Since, the formula for acceleration is given by :-

$\boxed{\sf{v = u + at}}$

$v = at$

$a = \dfrac{16.66}{120}$

$a = 0.138 m/s^2$

Now, distance travelled is given by formula,

$\boxed{\sf{2as = v^2 - u^2}}$

$2as = v^2$

$2\times0.138\times s = {16.66}^2$

$0.276 \times s = 277.55$

$s = \dfrac{277.55}{0.276}$

$s = 1005.6 m$