Question

a train starting from rest travels with uniform acceleration and acquires a velocity of 80 kilometre in 2 minutes find the acceleration distance travelled by the train this time​

Answer 1

Explanation:

v = 80 km /h = 22.22 m/s , u = 0

v = u + at

=> a = (v - u ) / t

=> a = 22.22 / 2 = 11.11 m/s² (Ans.)

v² - u² = 2as

=> s = (v²- u²)/2a

=> s = (22.22 × 22.22)/2×11.11 = 22.22 m (Ans.)

Answer 2

Explanation:

Given-

u= 0

v= 80km/hr= 22.22 m/sec.

t= 2 minutes= 120 seconds

a= ?

s= ?

we can find a by using 1st equation of motion,

v= u+at

22.22= 0+ a× 120

22.22= 0+ 120a

a= 22.22÷ 120

a= 0.185m/sec²

we can find s by using 3rd equation of motion,

v²= u²+ 2as

(22.22)²= (0)²+ 2× 0.185× s.

493.7284= 0+ 0.37 s.

s= 493.7284÷ 0.37

s= 1334.401 m

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