A train starting from rest travels with uniform acceleration and attains a velocity of 60kmh-1 in two minutes.. Find the distance covered by it
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By using v=u+at
60km/h=0km/h+ax2min
50/3m/s=a x 120s
a=50/3/120m/s²
a=5/36m/s²
Again,by using s=ut+1/2atxt
0x120s+1/2x5/36x120x120
Therefore,distance travelled by the train=1000m
or 1km
60km/h=0km/h+ax2min
50/3m/s=a x 120s
a=50/3/120m/s²
a=5/36m/s²
Again,by using s=ut+1/2atxt
0x120s+1/2x5/36x120x120
Therefore,distance travelled by the train=1000m
or 1km
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