A train starting from rest with an acceleration of 0.08 m/sec2 travels for 20 min calculate the velocity acquired and the distance travelled by the train
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a=0.08m/sec^2
t=20×60sec
s=1/2at^2
=1/2×0.08×(20×60)^2=57600m=57.6Km
============M
t=20×60sec
s=1/2at^2
=1/2×0.08×(20×60)^2=57600m=57.6Km
============M
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