Question

A train starting from rest with an acceleration of 0.5m/s² travels in 2 minutes. Calculate the velocity acquired and distance travelled by the train

Answer 1

Explanation:

u = 0 m/s, t = 120 sec

v = u + a*t = 0 + 0.5*120 = 60 m/s

s = 0 + 1/2 * 0.5*120^2 = 3600 m

= 3.6 km

Answer 2

Answer:

Explanation:

From equations of motion.

We have,

s=ut+1/2at²

Where s is the distance travelled

u=0(because the train starts from rest)

a is acceleration is 0.5m/s²

t that is time given is 2 minutes that is 120 seconds

Hence, putting values in the equation.

s=0*120+0.5*0.5*120*120

=3600mtrs

For current velocity, v

We have v=u+at

=0+0.5*120

= 60m/s