Question

A train starting from stationary position and moving with uniform acceleration attains a speed of 36km/h in 10 min. Find its acceleration.

Answer 1

as it moves from stationary position initial speed = 0
it attain a speed = 36km/h(final speed)= 10m/s
time taken= 10min=10*60=600sec 

so by v=u+at
10=0+a(600)
a=1/60=0.0166m/s²

Answer 2

if a train starts from stationary position then initial velocity of train = 0

moving uniform acceleration means constant acceleration .

given ,
final velocity ( V) = 36 km/h = 36× 5/18
= 10m/s

time taken = 10 minutes = 10× 60sec
= 600sec

use kinematics equation ,

V = u + at

10 = 0 + a × 600

a = 10/600 = 1/60 m/s²

a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²