A train starting from stationary position and moving with uniform acceleration attains a speed of36km per hour in 10 minutes. Find its acceleration
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Answered by
32
36 kmph = 36 × 5/18 m/s = 10 m/s
Acceleration = (v - u) / t
= (10 - 0) m/s / (10 × 60 s) ………[∵ train was initially at rest, u = 0]
= 0.0167 m/s²
Acceleration of train is 0.0167 m/s²
Acceleration = (v - u) / t
= (10 - 0) m/s / (10 × 60 s) ………[∵ train was initially at rest, u = 0]
= 0.0167 m/s²
Acceleration of train is 0.0167 m/s²
Answered by
37
Hi !
Initial velocity = u = 0 [ starting from rest ]
Final velocity = v =36 km/hr = 36*5/18 = 10 m/s
Time = t = 10 min = 10*60 = 600 sec
Acceleration = a = ?
a = v - u / t
= 10/600
= 0.016 m/s²
Acceleration = a = 0.016 m/s²
Initial velocity = u = 0 [ starting from rest ]
Final velocity = v =36 km/hr = 36*5/18 = 10 m/s
Time = t = 10 min = 10*60 = 600 sec
Acceleration = a = ?
a = v - u / t
= 10/600
= 0.016 m/s²
Acceleration = a = 0.016 m/s²
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