A train starting from stationary position and moving with uniform accelaration attains a speed of 36km/hour in 10 minutes.what is the distance travelled?
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u=0
v=36 kmph =10 ms^-1
t=10 min
By v=u+at
a=v\t=10\10 = 1ms^-2
& as s=ut + half at^2
s=half at^2. [u=0]
s=1\2 × 1 × 10 × 10
s= 50 m
hope u have understood it!!
v=36 kmph =10 ms^-1
t=10 min
By v=u+at
a=v\t=10\10 = 1ms^-2
& as s=ut + half at^2
s=half at^2. [u=0]
s=1\2 × 1 × 10 × 10
s= 50 m
hope u have understood it!!
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