Question

a train starting from stationary position and moving with uniform acceleration attains a speed of 36 km/hr in 10 minutes find the accelerations distance travelled during this time

Answer 1

Answer:

a = 1/60           distance = 3000m = 3km

Explanation:

from equations of motion : a = $\frac{v-u}{t}$ where( v = final velocity, u = initial velocity)

converting km/hr to m/s( SI unit)

36 * $\frac{5}{18}$ = 10 m/s  = v

10 min = 600 sec

and u = 0 since it starts from rest.

a = $\frac{10-0}{600}$ = 1/60

distance = ut + 1/2at² (from equations of motion)

              = 3000 m

NOTE ;

to convert km/hr to m/s we should multiply km/hr with 5/18 which could be derived using units and dimensions.

to convert m/s to km/hr we should multiply  m/s with 18/5.