a train starting from stationary position and moving with uniform accelerated motion attains a speed of 20m/s in 10s.find its acceleration
Answers
Answer:
a=2m/s^2
Explanation:
simply apply newton first equation of motion
v=u+at
train is starting from rest so u=0m/s
and t=10s v=20m/s
so putt the value in equation
20=0+a×10
a=20/10=2m/s^2
Given :
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 20 m/s
- Time (t) = 10 seconds
To find :
- Acceleration (a)
According to the question,
We know that,
⟹ v = u + at
Where,
- v stands for Final velocity
- u stand for Initial velocity
- t stands for Time
- a stands for Acceleration
⟹ Substituting the values,
⟹ 20 = 0 + a × 10
⟹ 20 - 0 = 10a
⟹ 20 = 10a
⟹ 20 ÷ 10 = a
⟹ 2 = a
.°. The acceleration is 2 m/s²...
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More details :
Acceleration :
The rate of change of its velocity with time is known as acceleration.
- SI unit is m/s².
- Acceleration is a vector quantity.
Uniform acceleration :
A body has a uniform acceleration if its velocity changes at a uniform rate.
Non uniform acceleration :
A body has a non uniform acceleration if its velocity increases by unequal amounts in equal intervals of time.