a train starting from stationary position and moving with uniform acceleration attends a speed of 36 km per hour and 10 minutes find acceleration
Answers
Answered by
2
if a train starts from stationary position then initial velocity of train = 0
moving uniform acceleration means constant acceleration .
given , final velocity ( V) = 36 km/h = 36× 5/18 = 10m/s
time taken = 10 minutes = 10× 60sec = 600sec
use kinematics equation ,
V = u + at
10 = 0 + a × 600
a = 10/600 = 1/60 m/s²
a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²
moving uniform acceleration means constant acceleration .
given , final velocity ( V) = 36 km/h = 36× 5/18 = 10m/s
time taken = 10 minutes = 10× 60sec = 600sec
use kinematics equation ,
V = u + at
10 = 0 + a × 600
a = 10/600 = 1/60 m/s²
a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²
cutiepiejyoti:
plz mark me as brainliest
thanks but l can't understood that how u solve its final velocity
ohh
as it moves from stationary position initial speed = 0
it attain a speed = 36km/h(final speed)= 10m/s
time taken= 10min=10*60=600sec
so by v=u+at
10=0+a(600)
a=1/60=0.0166m/s²
it attain a speed = 36km/h(final speed)= 10m/s
time taken= 10min=10*60=600sec
so by v=u+at
10=0+a(600)
a=1/60=0.0166m/s²
see ths
can u understand it now ??
ok
thanks
plz mark me as brainliest if u satisfy
Similar questions