a train starting from stationary position and moving with uniform acceleration attain a speed of 36km per hour in 10min. Find its acceleration...... ans:0.016m...somebody solve it
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HOLA!!
HERE WE GO
GIVEN
Initial velocity (u) = 0
Final velocity (v) = 36km/hr = 36000m/3600s
= 10m/s
time = 10 min = 10×60 =600s
acceleration = ?
SOLUTION
acceleration = (v- u)/ t
= ( 10 -0 )/600
= 10/600
= 1/60 (divide 1 by 60 to get ans)
= 0.016ms^-2
BY THE WAY REMEMBER
unit of acceleration here is ms^-2 and not m.
HOPE IT HELPS YOU :D
HERE WE GO
GIVEN
Initial velocity (u) = 0
Final velocity (v) = 36km/hr = 36000m/3600s
= 10m/s
time = 10 min = 10×60 =600s
acceleration = ?
SOLUTION
acceleration = (v- u)/ t
= ( 10 -0 )/600
= 10/600
= 1/60 (divide 1 by 60 to get ans)
= 0.016ms^-2
BY THE WAY REMEMBER
unit of acceleration here is ms^-2 and not m.
HOPE IT HELPS YOU :D
hyunxu:
thank you for the que chakshu :D
Thank u for solving it
it seems you r 1D Fan ...enjoy :D
oh yes I am and am currently waiting for me to come back
:D
:-D
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