a train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes find its acceleration
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We have,
v = u+at
where v = final velocity; u = initial velocity; a = acceleration and t = time taken.
v = 36km/hr = 10m/s
u = 0
t = 10min = 600s.
.°. 10 = 0 + 600a
a = 10/600 = (1/60)m/s
v = u+at
where v = final velocity; u = initial velocity; a = acceleration and t = time taken.
v = 36km/hr = 10m/s
u = 0
t = 10min = 600s.
.°. 10 = 0 + 600a
a = 10/600 = (1/60)m/s
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