Question

a train starting from stationary position and moving with uniform acceleration attend a speed of 36 km per hour in 10 minutes find its acceleration

Answer 1

36 km / h = 36 * 5 / 18 m / s = 10 m / s

U = 0 m /s

a = V - U / t

= 10 - 0 / 10 * 60

= 10 / 600

= 1 / 60 m / s ^ 2

Answer 2

Answer:

Given,
Initial velocity = 0 m/s

Final velocity = 36 k/h = 36 × 5/18 = 10 m/s

Time taken = 10 mins = 600 seconds = 10 × 60 secs

We know that,

Acceleration = v - u / t

∴ Acceleration = 10 - 0 / 10 × 60
= 10 / 600
= 1 / 60
= 0.1667 m/s²
= 0.1667 × 10^-1 m/s²
= 1.67 × 10^-2 m/s²


Hence, the acceleration of the train is 1.67 × 10^-2 m/s².

Hope it helps you !!

Be Brainly !!