a train starting from stationary positionand moving with uniform acceleration attain a speed of 36km/h in 10 minute . find its acceleration
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Answer:
= 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²
Explanation:
if a train starts from stationary position then initial velocity of train = 0
moving uniform acceleration means constant acceleration .
given ,
final velocity ( V) = 36 km/h = 36× 5/18
= 10m/s
time taken = 10 minutes = 10× 60sec
= 600sec
use kinematics equation ,
V = u + at
10 = 0 + a × 600
a = 10/600 = 1/60 m/s²
a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²
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