Question

a train starting from stationary positionand moving with uniform acceleration attain a speed of 36km/h in 10 minute . find its acceleration

Answer 1

Answer:

= 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²

Explanation:

if a train starts from stationary position then initial velocity of train = 0

moving uniform acceleration means constant acceleration .

given ,

final velocity ( V) = 36 km/h = 36× 5/18

= 10m/s

time taken = 10 minutes = 10× 60sec

= 600sec

use kinematics equation ,

V = u + at

10 = 0 + a × 600

a = 10/600 = 1/60 m/s²

a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²

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