Question

a train starting from stationery position and moving with uniform acceleration attains a speed of 36 km/h in 10 minutes. find the acceleration.

Answer 1

Hi there !!

As it is starting from stationery position ,

Initial velocity = u = 0 m/s

Given :

Final velocity = v = 36 km /hr = 36 × 5/18 = 10 m/s

acceleration = a 

Time = t = 10 min = 600 sec

According to Laws of Motions : -

v = u + at

a = [ v- u ] ÷ t
           
   = 10 ÷ 600
 
   = 0.166 m/s² [ approx .]

Answer 2

Hi there !!

________________________

Initial velocity,
                      u = 0 m/s


Final velocity,
                      v = 36 km /hr 
                         = (36 x 1000) / (60 x 60)
                         = 36000/3600
                         = 10 m/s


Time,
         t = 10 min
           = 600 sec

Acceleration, a = ?

According to First equation of motion

    v = u + at

a = (v-u) / t

    = (10-0) / 600
 
   = 10/600
  
   = 0.167 m/s

__________________

hope it helps