Question

A train starting from the rest attain a velocity of 96km/h in 8 minute. if acceleration is uniform then acceleration and distance travelled by train​

Answer 1

Answer:

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Answer 2

Answer:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Explanation:

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