a train starting from the rest moves with a uniform acceleration of 0.2 metre per second square for 5 minutes calculate the final velocity acquired and the distance travelled in this time
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acceleration= velocity upon time
velocity= acc.×time
=60 per sec
distance = velocity × time
= 18000m
velocity= acc.×time
=60 per sec
distance = velocity × time
= 18000m
rahulraghav:
how does 18000m comes
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