Question

a train starting from the rest moves with a uniform acceleration of 0.2m/s² for 5 min. calculate the final velocity acquired and the distance travelled in this time

Answer 1

v=u + at
v=0+0.2×5×60
v=60m/s
final velocity = 60 m/s

Answer 2

initial velocity = o ( the train starts from thr rest)
final velocity= ? (to be calculated)
acceleration = 0.2m/s^2
time = 5 min
convert 5 min into sec = 300 sec
v=u+at
v = 0+ 0.2 ×300
v= 60 m/s
distance travelled ( s) =(to be calculated )
s =ut+1/2at^2
s= 0×300+1/2×0.2×300^2
s= 18000 meter or 18 km ....
hope it help you