Question

a train starting from the rest moves with a uniform acceleration of 0.2 M per second square for 5 minutes calculate the final velocity and distance travelled​

Answer 1

a=v-u/t

the started from rest hence u(initial velocity) will be 0.

a=0.2;v=?;t=5×60=300s

0.2=v/300

300×0.2=v

60=v.

s (distance)=ut+1/2 at^2

s=1/2at^2 (since u=0)

s=1/2×0.2×300×300

s=9000m