Question

A train starting trom rest attains a velocity
of 72 km/h in 5 minutes. Assuming that
the acceleration is uniform, find the
acceleration and the distance travelled by
the train to attain this velocity.​

Answer 1

Answer:

Given,

Initial velocity=u=0m/s

Final velocity=V=72km/h

Time=5min

We will convert minutes into hours.

=560h=112h

We have to find out acceleration:

We will denote acceleration by a and distance travelled by s.

Formula used:

a=v−u/t ⇒a=72−0/112⇒a=72×12= 864km/h^2

Hence the acceleration is 864km/h^2.

Now, the distance travelled by train:

Formula used:

s=ut+1/2at^2=0×1/12+1/2(864)(1/12)^2=1/2×864×1/144=3km

Hence, the distance travelled by train is 3km.