Math, asked by sachinmangat1995, 23 days ago

A train starts form Station A with speed of 90
km/hr at 8:00 on towards Station B, in the route it
Crosses another train Starting from Station B towards
Station A at 9:00 am with a speed of 60Kmph, at
11:24 am. If both the trains take stoppage of 10 min
after every hour then they will cross each other at
what time?
a) 12:10pm
b) 12:15pm
c) 11:50am
d) 11:59 am
e) 12 noon​

Answers

Answered by araj3024
0

Answer:

A train starts form Station A with speed of 90

km/hr at 8:00 on towards Station B, in the route it

Crosses another train Starting from Station B towards

Station A at 9:00 am with a speed of 60Kmph, at

11:24 am. If both the trains take stoppage of 10 min

after every hour then they will cross each other at

answer is = d- 11:59 am

Answered by mukhopadhyaypratyush
1

Answer: e) 12 noon

Step-by-step explanation:

Train a reached 90 km from the point A at 9:00 am.

so, their crossing time is (11:24-9:00) = 2hrs 24 min or 12/5

D= S×T

(90+60)×12/5 = 360km . so, total distance AB = (90+360)=450 km.

in the 2nd condition, 60-10 = 50 min

Speed of Train A is 90×50 = 75km/hr

60

Speed of Train B is 50 km/h

Train A reached 75 km in an hour.

t = d/s

= (450-75)/(75+60)

=375/125

=3hrs

so, time = (9:00+3h) = 12:00 noon.

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