A train starts from a junction and is moving with uniform acceleration and attains a speed of 40 km/ hr in 10inutes.
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By using v=s/t
s=vt
s=40km/hrx5/18x600s
s=100/9m/sx600s
s=100/3x200m
s=20000/3m
Therefore distance travelled by the train=6666.67m
s=vt
s=40km/hrx5/18x600s
s=100/9m/sx600s
s=100/3x200m
s=20000/3m
Therefore distance travelled by the train=6666.67m
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