A train starts from a railway station and its motion is observed as follows. Find the average speed of the train in km/hr.
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Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
Hence verified……….
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
Hence verified……….
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