A train starts from a station A with speed 10m/s to station B and returns to station A with speed 20m/s.find Average speed and average velocity. Can anyone answer this question. Please.
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Hello Dear.
Here is the answer---
Let the Distance between the Station A and Station B is x m.
In First Case(From A to B).
∵ Time = Distance/Speed
⇒Time(T₁) = x/10 seconds.
In Second Case(From B to A).
Time(T₂) = x/20 seconds.
Total Time(T) = T₁ + T₂
= x/10 + x/20
= (2x + x)/20 seconds.
Total Distance = x + x
= 2x m.
Using the Formula,
Average Speed = Total Distance/Total Time
= 2x/(3x/20)
= 40/3 m/s.
∴ Average Speed of the entire journey is 40/3 m/ s
As displacement is zero
Average velocity = Displacement / Time
Zero
So average velocity is zero
Hope it helps
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