A train starts from a station and moves with a constant acceleration for 2 minutes. If it
a distance of 400m in this period , find the acceleration.
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Given that
Acceleration=2min
Unitial velocity=0m(u)
Final velocity =400m(v)
Therefore acceleration =v-u÷time taken
= 400m-0m÷120sec
=400÷120
=3.33m/s
Acceleration=2min
Unitial velocity=0m(u)
Final velocity =400m(v)
Therefore acceleration =v-u÷time taken
= 400m-0m÷120sec
=400÷120
=3.33m/s
anandimenon:
Hey Adi, i think you've got it wrong, 400 is not the final velocity, but the distance covered, No offence meant...
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