A train starts from a station and moves with a constant acceleration for 2 minutes. If it covers a distance of 600m in this period, find the acceleration?
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Answered by
4
S = ut + (1/2)at^2
600 = (1/2)a14400
a=1/12m/s.sq.
600 = (1/2)a14400
a=1/12m/s.sq.
Answered by
4
s = 600 m
t = 2 mins => 2×60 => 120 sec
u = 0 m/s
using second equation of motion ,
s = ut +1/2 at²
600 = 0(120) +1/2×a×(120)²
600 = 0+1/2 × a × 120 × 120
600 = 60×120×a
600/60 = 120a
=> 10 = 120 a
=> 10/120 = a
=> 1/12 m/s² = a
hope this helps
t = 2 mins => 2×60 => 120 sec
u = 0 m/s
using second equation of motion ,
s = ut +1/2 at²
600 = 0(120) +1/2×a×(120)²
600 = 0+1/2 × a × 120 × 120
600 = 60×120×a
600/60 = 120a
=> 10 = 120 a
=> 10/120 = a
=> 1/12 m/s² = a
hope this helps
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