Question

A train starts from a station and moves with a
constant acceleration for 2 minutes. If it covers a
distance of 400 m in this period, find the
acceleration​

Answer 1

Answer:

u = 0 m/s

t = 2 min = 120 sec

s = 400 m

Using second law of motion

s = ut+1/2at^2

400 = 1/2*a* 120*120

a = 0.055 m/s^2

 

Using first law of motion

v = u+at

v = 0.055*120 = 6.67 m/s

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Explanation: