A train starts from a station and moves with a constant acceleration for 2 minutes.if it covers a distance of 400m in this period,find acceleration
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T is 2m
That is 120 sec
S is 400 m
U is 0
S = ut + ½ at²
400 = 0×120+½×a×120²
400= ½ × 14400a
400 = 7200a
400÷7200 = a
0.055 = a
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That is 120 sec
S is 400 m
U is 0
S = ut + ½ at²
400 = 0×120+½×a×120²
400= ½ × 14400a
400 = 7200a
400÷7200 = a
0.055 = a
I home my answer will help u
If yes then plz mark me brainalist
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