. A train starts from a station and moves with a constant acceleration for 2
minutes. If it covers a distance of 400 m in this period, find the acceleration.
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Acceleration = 0.0275 m/s^2
*Explanation*
Total d covered= 400m
Total t taken= 120 sec
Therefore, speed v d/t = 400/120 = 3.3m/s
Acceleration = (v-u)/t
v = 3.3 m/s
u= 0 m/s (as train started from rest)
t= 120 sec
Therefore, acceleration = (3.3-0)/120 = 0.0275m/s^2
*Explanation*
Total d covered= 400m
Total t taken= 120 sec
Therefore, speed v d/t = 400/120 = 3.3m/s
Acceleration = (v-u)/t
v = 3.3 m/s
u= 0 m/s (as train started from rest)
t= 120 sec
Therefore, acceleration = (3.3-0)/120 = 0.0275m/s^2
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