Question

a train starts from a station and moves with a constant acceleration for 2 minutes if its cover a distance of 600 m in this period find the acceleration​

Answer 1

Answer:

Acceleration of the train = 0.0556 m/s^2

Explanation:

Given details:

Distance covered by the train (S)= 400 m.

Time taken for the travel (t) = 2 minutes = 2 * 60 seconds = 120 seconds.

Initial velocity = 0 m/s^2

Formula required:

We know that the equation of motion is

S = u*t + 1/2*a*t^2

Solution:

400 = 0*120  + 1/2 * a * 120^2

400 =  0 + a * 14400/2

400 = 7200*a

a = 400 / 7200

a = 0.0556

Acceleration = 0.0556 m/s^2

HOPE IT HELP YOU

Answer 2

Answer:

a=0.8333 m/s^2

Step-by-step explanation:

S= 1/2at^2

u=0(starts from rest)

time=2 min=120 sec

a=?

600=1/2 x a x 120^2

600=7200a

a=600/7200

a=0.8333 m/s^2