A train starts from a station and moves with a constant acceleration for 2 minutes .if it covers a distance of 400m in this period find its acceleration
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S = vi t + 1÷2 at2
Vi =0 So vi t = 0
S = 1÷2 at2
S = 0.5 a t2
A = S ÷ 0.5 t2
A = 400 ÷ 0.5 (120)2
A = 400 ÷ 7200
A = 0.055 m/s2
Vi =0 So vi t = 0
S = 1÷2 at2
S = 0.5 a t2
A = S ÷ 0.5 t2
A = 400 ÷ 0.5 (120)2
A = 400 ÷ 7200
A = 0.055 m/s2
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