Question

. A train starts from a station and moves with a constant acceleration for 2 minutes. If it

covers a distance of 400 m in this period, find the acceleration

Answer 1

given:

u=0
s=400
time =120s

s=ut+1/2at²
400=1/2*a*120²
800=a*120²
a=14400/800
=144/8
=18

Answer 2

u=0
s=400
time =120s

s=ut+1/2at²
400=1/2*a*120²
800=a*120²
a=14400/800
=144/8
=18
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