Question

A train starts from a station on and moves with a constant acceleration for 2 minutes. If it covers a distance of 400 m in this period, find the acceleration.

Answer 1

since the train starts from rest ( from station),

initial velocity (u)= 0m/s

time= 2 minutes= 120 seconds

distance (s)= 400m

s=ut+ 1/2at²

400 = 0×120+1/2×a×120²

400=0+14400a/2

400×2=14400a

800=14400a

14400a=800

a=800/14400

a=1/18

a=0.055...m/s²

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