Question

A train starts from Howrah station at Kolkata at 6am and stops at Kharagpur for 1 hour. It leaves Kharagpur to reach Jamsedpur at 11 am. If the distance between Kolkata and Jamsedpur is 320 km, at what speed did the train travel ?​

Answer 1

Answer:

80kmph

Step-by-step explanation:

time taken =6-11am excluding 1 hour when it stopped

4 hours is the time distance =320 km

speed =distance/time

dpeed=320/4

speed=80kmph

Answer 2

Answer:

Speed is 80km/hr.

Step-by-step explanation:

Time= (11 am -6 am)- 1 hour= 4 hours

Distance = 320 km.

Therefore,

Speed = Distance/ Time

Speed = 320km/4 hours

Speed = 80km/hr.