A train starts from Howrah station at Kolkata at 6am and stops at Kharagpur for 1 hour. It leaves Kharagpur to reach Jamsedpur at 11 am. If the distance between Kolkata and Jamsedpur is 320 km, at what speed did the train travel ?
Answers
Answered by
4
Answer:
80kmph
Step-by-step explanation:
time taken =6-11am excluding 1 hour when it stopped
4 hours is the time distance =320 km
speed =distance/time
dpeed=320/4
speed=80kmph
Suchandan:
Yes it is correct.
Answered by
1
Answer:
Speed is 80km/hr.
Step-by-step explanation:
Time= (11 am -6 am)- 1 hour= 4 hours
Distance = 320 km.
Therefore,
Speed = Distance/ Time
Speed = 320km/4 hours
Speed = 80km/hr.
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