Question

A train starts from rest and accelerate uniformly at the rate of 5 m/s^2 for 5sec.Calculate the velocity of train in 5sec

Answer 1

Answer: →As per the information given in question →the train starts from rest hence,initial velocity(u)=0m/s →and the acceleration given in the question =a=5m/s² →the time after which the velocity has been asked = t=5sec →so,we have a,u,and t →so, we should use here the first equation of motion →i.e.v=u+at Explanation: →v=u+at →v=0+5×5 →v=0+25 →v=25 →hence,after applying the first equation of motion we find that the final velocity of train after 5 seconds will be equal to 25m/s

Answer 2

Answer:

$\large{\underline{\boxed{\sf v= 25 m/s}}}$

Explanation:

Given that;

Initial velocity (u) = 0 m/s

Acceleration (a) = 5 m/s²

Time (t) = 5 secs

To find: The velocity of the train.

Solution:

To find the final velocity, we can use first equation of motioy.

• v = u + at

⇒ v = 0 + 5 * 5

⇒ v = 25

Hence, the final velocity of the train is 25 m/s.

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The three equations of motion are;

• v = u + at
• s = ut + ½ at²
• v² - u² = 2as