Question

A train starts from rest and accelerate uniformly at the rate of 5 m/s2 for 5 seconds. Calculate the velocity of train in 5 sec.

Answer 1

Given :

• Train starts from rest , u=0
• a= 5m/sec²
• t = 5sec

To find :

velocity of train in 5 sec.

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion .

$\bf\:v=u+at$

$\bf\:s=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2as$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

Solution :

By using equation of motion

$\sf\:v=u+at$

$\implies\sf\:v=0+5\times5$

$\sf\implies\:v=25ms{}^{-1}$

Therefore ,velocity of train in 5 sec is 25 m/s

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As train starts from rest)

Acceleration, a = 5 m/s²

Time taken, t = 5 seconds

To Find,

Final velocity, v = ??

According to the 1st equation of motion,

We know that

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 5 × 5

⇒ v = 5 × 5

⇒ v = 25 m/s

Hence, the final velocity of train is 25 m/s.