Question

A train starts from rest and accelerate uniformly at the rate of 5 m/s2 for 5 sec. Calculate the velocity of train in 5 sec

Answer 1

Answer:

Explanation:

Here u=0 ,

a= 5m/s2 ,

t= 5 sec,

v=?

Now  

v = u + a t

 

v  =  0  +  5  ×  5

= 25  m/s

Answer 2

GIVEN :-

• Initial velocity , v = 0 m/s. [Train starts from rest]
• Time , t = 5 seconds.
• Acceleration , a = 5 m/s².

TO FIND :-

• The Final velocity , v.

SOLUTION :-

$\\ \bigstar \underline{ \displaystyle \sf \: Third \: Equation \: Of \: Motion.}$

$: \implies\displaystyle \sf \: v = u + at.$

• v = Final velocity.
• u = initial velocity.
• a = Acceleration.
• t = Time taken.

$\\ : \implies\displaystyle \sf \: v = 0 + 5 \times 5$

$: \implies\displaystyle \sf \: v = 0 + 25$

$: \implies \underline{ \boxed{\displaystyle \sf \: v = 25 \: ms ^{ - 1} }}$

$\therefore \underline{ \displaystyle \sf \: Velocity \ of \ train \ in \ 5 \ second \ is \ 25 m/s.}$

_____________________

$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(1)} = v = u + at.$

$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(2)} = s = ut + \dfrac{1}{2} at^{2}$

$\dashrightarrow \displaystyle \sf Equation \ of \ motion_{(3)} = v^{2} - u^{2} = 2as$